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3-2.Motion in Plane
easy
The angular velocity of seconds hand of a watch will be
A$\frac{\pi }{{60}}\ rad/\sec $
B$\frac{\pi }{{30}}\ rad/sec$
C$60\,\pi \,\,rad/sec$
D$30\,\pi \,\,rad/sec$
Solution
We know that second's hand completes its revolution $(2p)$ in $60\ sec$
$\omega = \frac{\theta }{t} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}rad/sec$
$\omega = \frac{\theta }{t} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}rad/sec$
Standard 11
Physics
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